I answered some 1 who asked what 1 would gain by using 2 × voltage, I said that = 2 × the power, but that = only a rise in speed of 10 to 13.
Now I see that if 1 goes @ the same speed as before, 1 gets the square root of 2, or about 1·4 × the power. (as well as the 2× voltage being used ½ the time, the motor is using it ½ the time.)
Have I got this right? (I know 1 could burn out motor if going 2× as fast.)
Now I see that if 1 goes @ the same speed as before, 1 gets the square root of 2, or about 1·4 × the power. (as well as the 2× voltage being used ½ the time, the motor is using it ½ the time.)
Have I got this right? (I know 1 could burn out motor if going 2× as fast.)