Making a lightbulb discharger

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk
Hello,

I'd like to make a lightbulb discharger to easily check the "healthyness" of my batteries.

I found these 200W lightbulb:
http://www.ebay.co.uk/itm/GLS-Pearl-Bulbs-100W-150W-200W-In-Bayonet-B22-Edison-Screw-E27-Cap-Fitting-/281316289122?pt=UK_Light_Bulbs&var=&hash=item417fc1ea62

And they can be connected to this holder:
http://www.ebay.co.uk/itm/Edison-Screw-ES-E27-Light-Bulb-Lamp-Holder-Socket-With-Terminal-Block-10M-Thread-/360986919304?pt=LH_DefaultDomain_3&hash=item540c7f4188

Let say now I want to discharge my 48V and 72V batteries:
- How do I know if the voltage is correct for the lightbulb? would that be too high?
- How do I make sure it discharge at the right wattage? I suppose a 100W lightbulb isn't going to discharge at 100W on a 48V and 72V battery?
- Is the blue line for positive and brown for negative?
- Can I put them in serie to increase wattage?

Thank you so much
 

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk

trex

Esteemed Pedelecer
May 15, 2011
7,703
2,671
that kit comes with 4 x 200W power resistors.
It's suitable for fast discharging 36V and48V batteries.

 
  • Like
Reactions: cwah

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk
I think I've found my answer:
http://www.practicalmachinist.com/vb/general/120v-bulbs-dc-148591/index2.html

- AC lightbulb use the same power whether it's on AC or DC.
- So I=P/V = 200W/200V = 0.9I.
- P = V*I = 48V*0.9I= 43.2W.

So each lightbulb would discharge at 43W. If I want to discharge at 400W I'd need to have 10 of them in parallel.

Because it's AC, positive or negative doesn't matter and I can plug the wire on the brown or blue either way.

Is that correct?

Thank you
 

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk
that kit comes with 4 x 200W power resistors.
It's suitable for fast discharging 36V and48V batteries.

Thanks I didn't noticed the resistors. But it's going to be way more expensive than my lightbulb option and customs are going to hit me hard when they'll find these big resistors also.

The big benefit of this tool is that it can have a low voltage cut off
 

trex

Esteemed Pedelecer
May 15, 2011
7,703
2,671
you need a discharge current around 4A. The light bulbs with that range of current are 12V 50W halogen bulbs.
divide your battery voltage by 12V, that will be 4 bulbs (3 not enough, the inrush current may damage your bulbs) for the 36V battery and 5 bulbs for the 48V battery.
Put these bulbs in series. You have your first array.
 
  • Like
Reactions: cwah and SRS

awol

Esteemed Pedelecer
Sep 4, 2013
1,216
374
Maybe put a watt meter between your battery and bulbs to tell you the amps.
 
D

Deleted member 4366

Guest
230v light bulbs are not good to use as a resistive load because the resistance changes so much with temperature. At 230v, they heat right up to whitevhot, but at only 72v, they probably won't even glow. The working resisistance might be about 200 ohms, but, when cold, it could be anything from 7 ohms to 2000 ohm depending on the material of the filament. It would be better to use a bank of 12v bulbs, which wiĺ get up to working temperature, or better still, the elament from one of those old electric fires that use a coil of wire around a ceramic bar. You can use a big crocodile clip to change the length and resistance. Maybe something like this:

http://pages.ebay.com/link/?nav=item.view&id=291355163362&alt=web
 
  • Like
Reactions: cwah

VictoryV

Esteemed Pedelecer
Feb 15, 2012
310
208
78
near Biggleswade
230v light bulbs are not good to use as a resistive load because the resistance changes so much with temperature. At 230v, they heat right up to whitevhot, but at only 72v, they probably won't even glow. The working resisistance might be about 200 ohms, but, when cold, it could be anything from 7 ohms to 2000 ohm depending on the material of the filament. It would be better to use a bank of 12v bulbs, which wiĺ get up to working temperature, or better still, the elament from one of those old electric fires that use a coil of wire around a ceramic bar. You can use a big crocodile clip to change the length and resistance. Maybe something like this:

http://pages.ebay.com/link/?nav=item.view&id=291355163362&alt=web
Try a mains fan heater, at 1000 watts the resistance is 57 ohms, at 2000 watts the resistance is 28 ohms and at 3000 watts the resistance is 19 ohms, so the 3000 watts setting would draw about 4 amps from 72 volt battery.

So you start at 1000 watts, then switch thru to 2000 watts, and finally to 3000 watts so avoiding a surge current.

Or... use an old 3000 watt kettle!

I use a 12v 50 watt inspection lamp to do the same for my wife's 12volt wheelchair battery which draws about 4 amps.
 
Last edited:

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk
230v light bulbs are not good to use as a resistive load because the resistance changes so much with temperature. At 230v, they heat right up to whitevhot, but at only 72v, they probably won't even glow. The working resisistance might be about 200 ohms, but, when cold, it could be anything from 7 ohms to 2000 ohm depending on the material of the filament. It would be better to use a bank of 12v bulbs, which wiĺ get up to working temperature, or better still, the elament from one of those old electric fires that use a coil of wire around a ceramic bar. You can use a big crocodile clip to change the length and resistance. Maybe something like this:

http://pages.ebay.com/link/?nav=item.view&id=291355163362&alt=web
Thanks d8veh, again you have an excellent idea.

I found this:
http://www.ebay.co.uk/itm/Nichrome-Wire-Resistance-Nickel-Chrome-Heating-Element-Hot-Cutting-Various-Sizes-/251550106470?pt=LH_DefaultDomain_3&var=&hash=item3a918e0366

It's cheap and good.. and with a resistance table!

The smallest wires 32 SWG have a resistance of 18. So if I buy 2 meter of this I'd have in serie a resistance of 36.

So, I'd discharge at 48V^2/36R = 64W.

Is that correct?
 

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk
Is there a simple way for me... to either discharge at 50W or 1000W for my 48V battery? I need to either test at low discharge while creating a pack, then high discharge when the pack is finished
 

trex

Esteemed Pedelecer
May 15, 2011
7,703
2,671
you'd need the FYD10-H for that.
It's very difficult to do a controlled discharge with light bulbs.You double the number of bulbs to halve the Amps and you have to keep an eye on the watt meter.
The nearest solution is a 2KW electric bar heater with battery croccodile clips. You move the clip up to lower the Amps.
I would not use the thermo wires, very difficult to make a bar heater with your own wires.
 

VictoryV

Esteemed Pedelecer
Feb 15, 2012
310
208
78
near Biggleswade
RIL700 Lamp.jpg
Is there a simple way for me... to either discharge at 50W or 1000W for my 48V battery? I need to either test at low discharge while creating a pack, then high discharge when the pack is finished
RING "RIL 700" 12 Volt 50 watt inspection light last price 9.99.

For a 48 volt battery, 4 of these in series to take up the 48 volts will provide a 50 watt load.
For a 1000 watt load u will still need the 4 in series but then 20 sets of the 4 bulbs in series, but connected in parallel !!!! (20 x 50 = 1000)
 
D

Deleted member 4366

Guest
Use that resistor that I showed you above. Connect your battery and away you go.
 
  • Like
Reactions: VictoryV

trex

Esteemed Pedelecer
May 15, 2011
7,703
2,671
you still make a bar heater with that wire and would need a ceramic rod and a barbecue to keep that wire from burning the house down.
 
  • Like
Reactions: VictoryV

D8ve

Esteemed Pedelecer
Jan 30, 2013
2,142
1,294
Bristol
Cwah
If the device heats up the resistance will change.
So the plane wire combo won't work.
The 12 volt bulb and watt meter combo is the best.
 

cwah

Esteemed Pedelecer
Jun 3, 2011
3,048
179
www.whatonlondon.co.uk
I think I found out the solution, although not as cheap as I'd like:
- Buy 3 of these, so 9 x 100w lightbulb:
http://www.ebay.co.uk/itm/X3-100W-ES-PEARL-48V-50V-GLS-LAMP-LIGHT-BULB-LOW-VOLTAGE-/140874761935?pt=UK_Light_Bulbs&hash=item20ccca46cf

- And these holder:
http://www.ebay.co.uk/itm/10pcs-E27-Socket-Plastic-Light-Lamp-Holder-Base-AC250V-6A-/321491993135?pt=LH_DefaultDomain_3&hash=item4ada6a822f

So if I want low 50w discharge, I can just plug 2 bulb in serie. And for high discharge, I put the 9 bulb in parallel

About £45 for the whole set up